3q^2-13q+12=0

Solution for 3q^2-13q+12=0 equation:

Simplifying
3q2 + -13q + 12 = 0

Reorder the terms:
12 + -13q + 3q2 = 0

Solving
12 + -13q + 3q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(4 + -3q)(3 + -1q) = 0

Subproblem 1
Set the factor '(4 + -3q)' equal to zero and attempt to solve:

Simplifying
4 + -3q = 0

Solving
4 + -3q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -3q = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -3q = 0 + -4
-3q = 0 + -4

Combine like terms: 0 + -4 = -4
-3q = -4

Divide each side by '-3'.
q = 1.333333333

Simplifying
q = 1.333333333
Subproblem 2
Set the factor '(3 + -1q)' equal to zero and attempt to solve:

Simplifying
3 + -1q = 0

Solving
3 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1q = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1q = 0 + -3
-1q = 0 + -3

Combine like terms: 0 + -3 = -3
-1q = -3

Divide each side by '-1'.
q = 3

Simplifying
q = 3
Solution
q = {1.333333333, 3}